Posted by Padilla 8:41 PM
Sorry to hijack, but...........

I was just dealt K-K in consecutive hands during a tournament.

1st one doubled me up.
2nd one flopped a set and knocked out an opponent holding A-A. (he never saw it coming)

Let's disregard the amazing A-A coincidence and get to the meat of it....
What genius knows the probability of being dealt the exact same hand 2 times in a row.
(if you say 50-50, your level of comedic humor will be revealed)

No, I did not hit the same suits on hand #2.

p.s. I lost the damn tourney. I hate Turbo's and accidentally registered for it. Those Pokerstars titles are too long, I didn't notice it.

3 Comment(s):

Posted by  Johnnymac, at 6:02 AM, February 23, 2006  

There are other regular contributors/readers here who know this stuff better than me, but the odds of being dealt a specific pocket pair (eg AA, KK, QQ, 33, etc) on any hand is roughly 0.45% ([(4/52) x (3/51)]), or 220:1, so the odds of it happening on consecutive hands would be (0.45%)^2, or 0.00205% or 48840:1.



No?

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Posted by  Anonymous, at 8:28 AM, February 23, 2006  

And the odds of winning both of them are 99 trillion to 1.

If it weren't for luck...

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Posted by  Dr Fro, at 1:06 PM, February 23, 2006  

true, getting a particular hand consecuutively is (1/221)^2.

But getting any pair in consecutive hands (which would have been labeled equally amazing) is 13 times more likely.

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